# Calculate CE for each trial then get the mean
((93 - 100) + (103 - 100) + (99 - 100) + 
 (105 - 100) + (96 - 100)) / 5[1] -0.8
KINESIOL 2MC3 
 
 Lab 1
A person is tasked with learning to project a slider down a fixed track to a specified goal distance of 100 cm using their non-dominant hand. The person performs 5 trials of this task. On each trial, you record the distance the slider traveled from the start point (wooden barrier).
The result for each trial is shown below:
Q1: How should we measure performance on this task?
Q2: What type of measure would this be?
Q3: How would you classify this task?
We can calculate using: \(Mean \,CE = \sum(x_{i} - T)/n\)
Mean CE = -0.8 cm
What do we learn from this?
We can calculate using: \(Mean \,VE = \sqrt{\sum(x_{i} - M)^2/n}\)
[1] 99.2
# Step 2: Calculate squared difference then get mean
sqrt(((99 - 99.2)^2 + (99 - 99.2)^2 + (99 - 99.2)^2 + 
      (99 - 99.2)^2 + (100 - 99.2)^2) / 5)[1] 0.4
Mean VE = 0.4 cm
We can calculate using: \(Mean \,AE = \sum|x_{i} - T|/n\)
# Calculate absolute difference for each trial then get mean
(abs(93 - 100) + abs(103 - 100) + abs(99 - 100) + 
 abs(105 - 100) + abs(96 - 100)) / 5[1] 4
Mean AE = 4 cm \(\longrightarrow\) How do we interpret this?
[1] 0
# Calculate AE
(abs(98 - 100) + abs(96 - 100) + abs(104 - 100) + 
 abs(102 - 100) + abs(100 - 100)) / 5[1] 2.4
What do we learn from this?
| Person | Trial 1 | Trial 2 | Trial 3 | Trial 4 | Trial 5 | 
|---|---|---|---|---|---|
| Jae | 80 | 90 | 85 | 82 | 87 | 
| Diane | 95 | 105 | 100 | 97 | 102 | 
If we calculated mean CE, mean VE, and mean AE for each person…
| Person | CE | VE | AE | 
|---|---|---|---|
| Jae | -15.2 | 3.54 | 15.2 | 
| Diane | -0.2 | 3.54 | 3.0 | 
We can calculate using by taking the absolute value of our calculated CE:
# Calculate mean CE as before but afterwards take the absolute
abs(((93 - 100) + (103 - 100) + (99 - 100) + 
    (105 - 100) + (96 - 100)) / 5)[1] 0.8
Mean |CE| = 0.8 cm \(\longrightarrow\) How do we interpret this?
We can calculate using: \(Mean \,E = \sqrt{\sum(x_{i} - T)^2/n}\)
# Calculate squared difference then get mean
sqrt(((93 - 100)^2 + (103 - 100)^2 + (99 - 100)^2 + 
      (105 - 100)^2 + (96 - 100)^2) / 5)[1] 4.472136
Mean E = 4.47 \(\longrightarrow\) How do we interpret this?